1 /* Test of rounding towards negative infinity.
2 Copyright (C) 2007 Free Software Foundation, Inc.
4 This program is free software; you can redistribute it and/or modify
5 it under the terms of the GNU General Public License as published by
6 the Free Software Foundation; either version 2, or (at your option)
9 This program is distributed in the hope that it will be useful,
10 but WITHOUT ANY WARRANTY; without even the implied warranty of
11 MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
12 GNU General Public License for more details.
14 You should have received a copy of the GNU General Public License
15 along with this program; if not, write to the Free Software Foundation,
16 Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301, USA. */
18 /* Written by Bruno Haible <bruno@clisp.org>, 2007. */
28 #include "isnanl-nolibm.h"
30 #define ASSERT(expr) \
35 fprintf (stderr, "%s:%d: assertion failed\n", __FILE__, __LINE__); \
44 DECL_LONG_DOUBLE_ROUNDING
46 BEGIN_LONG_DOUBLE_ROUNDING ();
49 ASSERT (floorl (0.0L) == 0.0L);
50 ASSERT (floorl (-0.0L) == 0.0L);
51 /* Positive numbers. */
52 ASSERT (floorl (0.3L) == 0.0L);
53 ASSERT (floorl (0.7L) == 0.0L);
54 ASSERT (floorl (1.0L) == 1.0L);
55 ASSERT (floorl (1.5L) == 1.0L);
56 ASSERT (floorl (1.999L) == 1.0L);
57 ASSERT (floorl (2.0L) == 2.0L);
58 ASSERT (floorl (65535.999L) == 65535.0L);
59 ASSERT (floorl (65536.0L) == 65536.0L);
60 ASSERT (floorl (2.341e31L) == 2.341e31L);
61 /* Negative numbers. */
62 ASSERT (floorl (-0.3L) == -1.0L);
63 ASSERT (floorl (-0.7L) == -1.0L);
64 ASSERT (floorl (-1.0L) == -1.0L);
65 ASSERT (floorl (-1.001L) == -2.0L);
66 ASSERT (floorl (-1.5L) == -2.0L);
67 ASSERT (floorl (-1.999L) == -2.0L);
68 ASSERT (floorl (-2.0L) == -2.0L);
69 ASSERT (floorl (-65535.999L) == -65536.0L);
70 ASSERT (floorl (-65536.0L) == -65536.0L);
71 ASSERT (floorl (-2.341e31L) == -2.341e31L);
72 /* Infinite numbers. */
73 ASSERT (floorl (1.0L / 0.0L) == 1.0L / 0.0L);
74 ASSERT (floorl (-1.0L / 0.0L) == -1.0L / 0.0L);
76 ASSERT (isnanl (floorl (0.0L / 0.0L)));